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Target Audience

The Oracle 1z0-071 exam is designed for those professionals who have some level of experience in operating with Oracle SQL and PL/SQL technologies and want to improve their expertise to perform the job roles of a Database Administrator or a Developer.

Oracle 1z1-071 (Oracle Database SQL) exam is a highly sought-after certification for anyone looking to pursue a career in database administration. It is a test that measures the skills and knowledge of individuals who have expertise in SQL programming, database development, and database management. 1z0-071 Exam is designed to test the candidates’ ability to write, execute, and optimize SQL queries, as well as their understanding of the fundamental concepts of relational databases, Data Definition Language (DDL), Data Manipulation Language (DML), and transactions.

Achieving Oracle 1z1-071 certification is a valuable asset for professionals in the technology industry. Oracle Database SQL certification demonstrates a high level of technical expertise and knowledge in database management, and can lead to career advancement opportunities and higher salaries.

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Oracle Database SQL Sample Questions (Q146-Q151):

NEW QUESTION # 146
Examine the description of the ORDERS table:

Which three statements execute successfully?

A. SELECT * FROM orders
MINUS
SELECT * FROM INVOICES ORDER BY 1
B. SELECT * FROM orders ORDER BY order_ id
UNION
SELECT * FROM invoices;
C. SELECT order_ id, invoice_ data order_ date FROM orders
MINUS
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY invoice_ id;
D. SELECT * FROM orders ORDER BY order_ id
INTERSEOT
SELECT * FROM invoices ORDER BY invoice_ id;
E. SELECE order _id, order _ date FRON orders
LNTERSECT
SELECT invoice_ id, invoice_ id, order_ date FROM orders
F. (SELECT * FROM orders
UNION ALL
SELECT* FROM invoices) ORDER BY order _id;
G. SELECT order_ id, order_ data FROM orders
UNION ALL
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY order_ id;

Answer: B,F,G

Explanation:
In Oracle SQL, set operations like UNION, UNION ALL, INTERSECT, and MINUS can be used to combine results from different queries:
* Option A:
* Combining results using UNION ALL followed by ORDER BY will execute successfully because UNION ALL allows duplicate rows and ORDER BY can be used to sort the combined result set.
* Option E:
* Similar to option A, UNION ALL combines all rows from the two selects and allows ordering of the results.
* Option G:
* UNION combines the results from two queries and removes duplicates, and ORDER BY can be used to sort the final result set.
Options B, C, D, and F are incorrect because:
* Option B: You cannot intersect different columns (ORDER_ID with INVOICE_ID).
* Option C: Incorrect column names and syntax with ORDER BY.
* Option D: ORDER BY cannot be used before a set operator like INTERSECT.
* Option F: ORDER BY cannot be used directly after a MINUS operator without wrapping the MINUS operation in a subquery.

NEW QUESTION # 147
BOOK_SEQ is an existing sequence in your schema.
Which two CREATE TABLE commands are valid?
A)

B)

C)

D)

E)

A. Option E
B. Option C
C. Option D
D. Option B
E. Option A

Answer: A,D

NEW QUESTION # 148
You must find the number of employees whose salary is lower than employee 110.
Which statement fails to do this?

A. SELECT COUNT (*)
FROM employees e
JOIN (SELECT salary FROM employees WHERE employee_ id= 110) a
ON e. salary< a. salary;
B. SELECT COUNT (* )
FROM employees
WHERE salary < (SELECT salary FROM employees WHERE employee id =
110) ;
C. SELECT COUNT (* )
FROM employees e
WHERE e. salary < (SELECT a. salary FROM employees a WHERE e. employee_ id = 110);
D. SELECT COUNT (*)
FROM employees
JOIN employees a
ON e. salary< a. salary
WHERE a. employee_ id= 110;

Answer: C

Explanation:
In this context, the correct answers will provide a count of employees with a salary less than that of employee with ID 110. Let's evaluate the provided statements:
* A: This statement is incorrect due to a syntax error; it uses alias 'e' without defining it, and 'a' is also used incorrectly in the JOIN clause. It should have been written with proper aliases.
* B: This statement is correct as it uses a subquery to find the salary of employee ID 110 and compares it to the salaries of all employees to get the count.
* C: This statement is also correct as it creates a derived table with the salary of employee ID 110 and compares it with the salaries of the 'employees' table using a JOIN.
* D: This is the statement that fails. It is incorrect because the subquery references 'e.employee_id = 110', which will compare the salary of each employee to themselves if their ID is 110, not to the salary of employee 110 for all employees.

NEW QUESTION # 149
Examine the commands used to create department details and course details:

You want to generate a list of all department IDs that do not exist in the COURSE_DETAILS table. You execute the SQL statement:

What is the outcome?

A. it fails because the Join type used is Incorrect
B. It executes successfully and displays the required list.
C. It executes successfully but displays an incorrect list.
D. It fails because the ON clause condition is not valid

Answer: A

NEW QUESTION # 150
Examine the SQL statement used to create the TRANSACTION table. (Choose the best answer.) SQL > CREATE TABLE transaction (trn_id char(2) primary key,
Start_date date DEFAULT SYSDATE,
End_date date NOT NULL);
The value 'A1' does not exist for trn_id in this table.
Which SQL statement successfully inserts a row into the table with the default value for START_DATE?

A. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE('SYSDATE+10'))
B. INSERT INTO transaction (trn_id, end_date) VALUES ('A1', '10-DEC-2014')
C. INSERT INTO transaction (trn_id, start_date, end_date) VALUES ('A1', , '10-DEC-2014')
D. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE(DEFAULT+10))

Answer: B

NEW QUESTION # 151
......

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